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AP EAMCET2002MathematicsCircle

The equation of the circle of radius 5 and touching the co-ordinate axes in third quadrant is

Options

  1. A(x-5)^2+(y+5)^2=25
  2. B(x+5)^2+(y+5)^2=25
  3. C(x+4)^2+(y+4)^2=25
  4. D(x+6)^2+(y+6)^2=25

Correct answer

B. (x+5)^2+(y+5)^2=25

Step-by-step solution

Since the circle touches the coordinate axes in third quadrant therefore. centre of the circle is (-5,-5) Then equation of circle is, (x+5)^2+(y+5)^2=25 .

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