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AP EAMCET2001MathematicsCircle

The equation of the normal to the circle x^2+y^2+6 x+4 y-3=0 at (1,-2) is

Options

  1. Ay+1=0
  2. By+2=0
  3. Cy+3=0
  4. Dy-2=0

Correct answer

B. y+2=0

Step-by-step solution

Given circle is x^2+y^2+6 x+4 y-3=0 Equation of the tangent at (x₁, y₁ ) is x x₁+y y₁+3 (x+x₁ )+2 (y+y₁ )-3=0 If this line passes through (1,-2) , then array rrr & x-2 y+3(x+1)+2(y-2)-3=0 & x-2 y+3 x+3+2 y-4-3=0 & 4 x-4=0 & x-1=0 array Equation of the normal is 0 x-1 y= It passes through (1,-2) aligned -(-2) & = =2 -y & =2 y+2=0 aligned

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