AP EAMCET2001MathematicsCircle
If the polar of a point on the circle x^2+y^2=p^2 with respect to the circle x^2+y^2=q^2 touches the circle x^2+y^2=r^2 , then p, q, r are in
Options
- AAP
- BGP
- CHP
- DAGP
Correct answer
B. GP
Step-by-step solution
We have, polar equation with respect to x^2+y^2=p^2 is x x₁+y y₁=q^2 This equation touches the circle x^2+y^2-r^2=0 aligned & Then, r= 0+0-q^2 x₁^2+y₁^2 & -q^2=r x₁^2+y₁^2 -q^2=r p^2 & -q^2= r p q^2=p r & aligned Thus p, q and r in GP.