A parallel-plate capacitor of 50 F contains a dielectric slab of constant ( k ) with the same dimensions. If a time-varying potential difference is applied at a rate of 50 V/s . What is the displacement current in the capacitor?

Step-by-step solution

The displacement current I_d in a capacitor is equal to the conduction current I_c flowing into it. I_d = I_c = dQ dt Since Q = CV , we have: I_d = C dV dt Given: C = 50 F = 50 10⁻⁶ F dV dt = 50 V/s Substituting the values: I_d = 50 10⁻⁶ 50 I_d = 2500 10⁻⁶ A I_d = 2.5 10⁻³ A = 2.5 mA Answer: 2.5 mA