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MHT CET 202625 AprilMorning Shift
Exam
MHT CET
Year
2026
Date
25 April
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Waves

MHT CET 2026 · 25 April · Morning Shift · Physics · Electromagnetic Waves

A parallel-plate capacitor of 50\ contains a dielectric slab of...

A parallel-plate capacitor of 50 μF50\ \mu\text{F} contains a dielectric slab of constant (kk) with the same dimensions. If a time-varying potential difference is applied at a rate of 50 V/s50\ \text{V/s}. What is the displacement current in the capacitor?

Options

  1. A5 mA5\ \text{mA}
  2. B2.5 mA2.5\ \text{mA}
  3. C3 mA3\ \text{mA}
  4. D1.5 mA1.5\ \text{mA}

Correct answer

B. 2.5 mA2.5\ \text{mA}

Step-by-step solution

The displacement current IdI_d in a capacitor is equal to the conduction current IcI_c flowing into it.

Id=Ic=dQdtI_d = I_c = \dfrac{dQ}{dt}

Since Q=CVQ = CV, we have:

Id=CdVdtI_d = C \dfrac{dV}{dt}

Given:
C=50 μF=50×10−6 FC = 50\ \mu\text{F} = 50 \times 10^{-6}\ \text{F}
dVdt=50 V/s\dfrac{dV}{dt} = 50\ \text{V/s}

Substituting the values:

Id=50×10−6×50I_d = 50 \times 10^{-6} \times 50

Id=2500×10−6 AI_d = 2500 \times 10^{-6}\ \text{A}

Id=2.5×10−3 A=2.5 mAI_d = 2.5 \times 10^{-3}\ \text{A} = 2.5\ \text{mA}

Answer: 2.5 mA2.5\ \text{mA}
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