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AP EAMCET20225 Jul 2022Morning ShiftMathematicsComplex NumberActual

The locus of a point z satisfying |z|^2= Re (z) is a circle with centre

Options

  1. A(0, 1 2 )
  2. B(- 1 2 , 0 )
  3. C( 1 2 , 0 )
  4. D(0,- 1 2 )

Correct answer

C. ( 1 2 , 0 )

Step-by-step solution

Let z=x+i y|z|= x^2+y^2 Now, |z|^2= Re (z)x^2+y^2=x x^2+y^2-x=0g=1 / 2, f=0 So, centre of circle ( 1 2 , 0 ) .

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