AP EAMCET202021 Sep 2020Evening ShiftMathematicsComplex NumberActual
The locus of (z ) satisfying ( | z-i z-2 i |=2 ) is a
Options
- AHyperbola
- BCircle
- CStraight line
- DEllipse
Correct answer
B. Circle
Step-by-step solution
It is given that, ( | z-i z-2 i |=2 ) Let (z=x+i y ), then ( aligned & |x+i(y-1)|=2|x+(y-2) i| & x^2+(y-1)^2=4 [x^2+(y-2)^2 ] & 3 x^2+3 y^2-14 y+16=0 represent a circle, so aligned ) locus of (z ) is a circle. Hence, option (b) is correct.