Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201922 Apr 2019Morning ShiftMathematicsComplex NumberActual

ft. |z- 1+3 i 2 |= 10 2 ) If (P, Q ) and (R ) are points, respectively representing the complex numbers (z, z e^ i 3 ) and (z (1+e^ i 3 ) ) in argand plane, then the area of the triangle (P Q R ), is

Options

  1. A( 3 |z|^2 )
  2. B( 3 2 |z|^2 )
  3. C( 3 4 |z|^2 )
  4. D(2 3 |z|^2 )

Correct answer

C. ( 3 4 |z|^2 )

Step-by-step solution

Given that, ( aligned P Q & = |z e^ i / 3 -z |=|z| |e^ i / 3 -1 | & =|z| | 3 +i 3 -1 | & =|z| |-2 ^2 6 +2 i 6 6 | & =|z| |2 6 | | 6 -i 6 |=|z| |2 1 2 ||1| aligned ) (P Q=|z| ) Now, ( aligned & Q R= [z (1+e^ i / 3 )-2 e^ i / 3 ] & Q R=|z| aligned ) Similarly, (P R=|z| ) so, (P Q=Q R=P R ) ( P Q R ) is equilateral triangle with side length ( 1 ). Now, area of ( P Q R= 3 4 |z|^2 )

Practice Complex Number on Quantrex Academy →

More from Complex Number

If z and are two non-zero complex numbers such that |z |=1 and Arg z- Arg = 2 then z = 2025Let z satisfy |z|=1, z=1- z and Im (z)>0 Statement-I : z is a real number Statement-II : Principal argument of z is 3 . Then 2025If ₁ and ₂ are two non-zero complex numbers and a , b are non zero real numbers such that | a ₁+ b ₂ |= | a ₁- b ₂ | , then ₁ ₂ is 2025If a complex number z=x+i y represents a point P on the Argand plane and Arg ( z-3+2 i z+2-3 i )= 4 , then the locus of P is a 2025By taking a i b =x i y, x>0 , if we get 21+12 2 i 21-12 2 i =a+i b , then b a = 2025Two values of (-8-8 3 i)^ 1 / 4 are 2025If x=3-2 3 i , then x^4-12 x^3+54 x^2-108 x-54= 2025z ₁, z ₂, z ₃ represent the vertices A , B , C of a triangle ABC respectively in the Argand plane. If |z₁-z₂ |= 25-12 3 , | z₁-z₃ z₂-z₃ |= 3 4 and ACB =30^ , then the area (in sq. 2025 Full Complex Number list All AP EAMCET PYQs