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AP EAMCET2009MathematicsComplex Number

The locus of z satisfying the inequality | z+2 i 2 z+i | < 1 , where z=x+i y , is

Options

  1. Ax^2+y^2 < 1
  2. Bx^2-y^2 < 1
  3. Cx^2+y^2>1
  4. D2 x^2+3 y^2 < 1

Correct answer

C. x^2+y^2>1

Step-by-step solution

Let z=x+i y Given, | z+2 i 2 z+i | 3 & x^2+y^2>1 array

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