AP EAMCET201921 Apr 2019Morning ShiftMathematicsContinuity and DifferentiabilityActual
The number of discontinuities in R for the function f(x)= x-1 x^3+6 x^2+11 x+6 is
Options
- A3
- B2
- C1
- D0
Correct answer
A. 3
Step-by-step solution
Given, aligned & f(x)= x-1 x^3+6 x^2+11 x+6 & f(x)= x-1 (x+1) (x^2+5 x+6 ) & f(x)= x-1 (x+1)(x+2)(x+3) aligned For is discontinuous, hence denominator is 0 . array ll & (x+1)(x+2)(x+3)=0 & x=-1,-2,-3 array Hence, number of discontinuous in R is 3 .