AP EAMCET2001MathematicsContinuity and Differentiability
If f(x)= x^2-10 x+25 x^2-7 x+10 and f is continuous at x=5 , then f(5) is equal to
Options
- A0
- B5
- C10
- D25
Correct answer
A. 0
Step-by-step solution
aligned f(5) & = _ x 5 f(x)= _ x 5 x^2-10 x+25 x^2-7 x+10 & = _ x 5 (x-5)^2 (x-5)(x-2) = _ x 5 x-5 x-2 & = 5-5 5-2 =0 aligned