NDA 2024
- Exam
- NDA
- Year
- 2024
- Subject
- Mathematics
- Chapter
- Basics of Mathematics
NDA 2024 · Mathematics · Basics of Mathematics
For x ≥ y > 1 , let _x((x)/(y))+ _y((y)/(x))=k , then the value of...
For
x≥y>1, let
logx(yx)+logy(xy)=k, then the value of
k can never be equal to:
Options
- A-1
- B−21
- C0
- D1
Step-by-step solution
logx(yx)+logy(xy)=k⇒logxx−logxy+logyy−logyx=k⇒1−logxy+1−logxy1=k Let, logxy=t∴2−t−t1=k⇒2t−t2−1=kt⇒t2+(k−2)t+1=0 For solution, D=b2−4ac≥0(k−2)2−4≥0(k−2)2≥0k−2≥2k−2≤0k≥4k≤0∴k≥4 or k≤0$
Hence,k \neq 1$.
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