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NDA 2013

Exam: NDA
Year: 2013
Subject: Mathematics
Chapter: Basics of Mathematics

NDA 2013 · Mathematics · Basics of Mathematics

What is the degree of the equation (1)/(x-3)=(1)/(x+2)-(1)/(2) ?

What is the degree of the equation \frac{1}{x-3}=\frac{1}{x+2}-\frac{1}{2}$ ?

Options

A $0$
B $1$
C $2$
D $3$

Correct answer

C. $2$

Step-by-step solution

\frac{1}{x-3}=\frac{1}{x+2}-\frac{1}{2}

\begin{aligned} & 2(x+2)=(x-3) \\ & 2 x+4+x^2-3 x=0 \\ & x^2-x+4=0\end{aligned}

$$

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