If the sixth term in the binomial expansion of (x^ - 8 3 +x^2 ₁₀ x )^8 is 5600 , then what is the value of x ?

Step-by-step solution

In the expansion of (x^ -8 / 3 +x^2 ₁₀ x )^8T₆= ^8 C₅ (x^ -8 / 3 )^3 (x^2 ₁₀ x )^5 5600=56 x⁻⁸ x¹⁰ ₁₀ x 56 x^2 ₁₀ x=5600 56 x^2 ₁₀ x=5600 x^2 ₁₀ x=100=(10)^2 ₁₀ 10 x=10 .