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NDA2019MathematicsBinomial TheoremActual

If the middle term in the expansion of (x^2+ 1 x )^ 2 x 184756 x¹⁰ , then what is the value of n ?

Options

  1. A10
  2. B8
  3. C5
  4. D4

Correct answer

A. 10

Step-by-step solution

(x^2+ 1 x )^ 2 n Its index is even aligned & Middle term =T_ n+1 & T_ n+1 = ^ 2 n C_n (x^2 )^n ( 1 x )^n & = ^ 2 n C_n x^n=184756 x¹⁰ aligned comparing power of x we get n=10

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