NDA2020MathematicsBinomial TheoremActual
If (1+2 x-x^2 )^6=a₀+a₁ x+a₂ x^2+ .+a₁₂ x¹² , then what is a₀-a₁+a₂-a₃+a₄- .+a₁₂ equal to?
Options
- A32
- B64
- C2048
- D4096
Correct answer
B. 64
Step-by-step solution
aligned & (1+2 x-x^2 )^6=a₀+a₁ x+a₂ x^2+ .+a₁₂ x¹² & Putting x=-1 & a₀-a₁+a₂+ .+a₁₂ = (1+2(-1)-(-1)^2 )^6 & =(1-2-1)¹²=(-2)^6=64 aligned