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NDA 2011
Exam
NDA
Year
2011
Subject
Mathematics
Chapter
Binomial Theorem

NDA 2011 · Mathematics · Binomial Theorem

What is the middle term in the expansion of (1-(x)/(2))^8 ?

What is the middle term in the expansion of (1−x2)8\left(1-\frac{x}{2}\right)^8 ?

Options

  1. A35x48\frac{35 x^4}{8}
  2. B17x58\frac{17 x^5}{8}
  3. C35x58\frac{35 x^5}{8}
  4. DNone of these

Correct answer

A. 35x48\frac{35 x^4}{8}

Step-by-step solution

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