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NDA 2025
Exam
NDA
Year
2025
Subject
Mathematics
Chapter
Continuity and Differentiability

NDA 2025 · Mathematics · Continuity and Differentiability

For the following two (02) items: Consider the function f(x) =...

For the following two (02) items:
Consider the function f(x)=f(x) =\begin{cases} 4(5^x), & x < 0 \\ 8k + x, & x \geq 0 \end{cases}$.<br><br>Ifthefunctioniscontinuous,thenwhatisthevalueof.<br><br>If the function is continuous, then what is the value ofk$?

Options

  1. A0.50.5
  2. B11
  3. C1.51.5
  4. D22

Correct answer

A. 0.50.5

Step-by-step solution

For the function to be continuous at x=0x = 0, the left-hand limit must be equal to the right-hand limit and the value of the function at x=0x = 0.

Left-hand limit at x=0x = 0 is given by:
lim⁡x→0−f(x)=lim⁡x→0−4(5x)=4(50)=4\lim_{x \to 0^{-}} f(x) = \lim_{x \to 0^{-}} 4(5^x) = 4(5^0) = 4

Right-hand limit at x=0x = 0 is given by:
lim⁡x→0+f(x)=lim⁡x→0+(8k+x)=8k+0=8k\lim_{x \to 0^{+}} f(x) = \lim_{x \to 0^{+}} (8k + x) = 8k + 0 = 8k

Equating the left-hand limit and the right-hand limit:
8k=48k = 4

k=48=0.5k = \dfrac{4}{8} = 0.5

Answer: 0.50.5
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