I=∫04π(tan3x+tanx)⋅dx=∫04πtan3x⋅dx+∫04πtanx⋅dx==∫04πtanx⋅tan2x⋅dx+∫04πtanx⋅dx∫04πtanx⋅(sec2x−1)⋅dx+∫04πtanx⋅dx=∫04πtanx⋅sec2x⋅dx−∫04πtanx⋅dx+∫04πtanx⋅dx=∫04πtanx⋅sec2x⋅dx Let tanx=z,dz=sec2x⋅dx∴∫tanx⋅sec2x⋅dx=∫z⋅dz=2z2+CwhereC=
constant\therefore I=\left[\frac{\tan ^2 x}{2}\right]_0^{\frac{\pi}{4}}=\frac{1}{2}-0=\frac{1}{2}$.