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NDA2015MathematicsDefinite IntegrationActual

Consider the integral I_m= ₀^ 2 m x x d x , where m is a positive integer. What is I ₁ equal to?

Options

  1. A0
  2. B1 2
  3. C1
  4. D2

Correct answer

A. 0

Step-by-step solution

I _ m = ₀^ 2 mx x dx I ₁= ₀^ 2 x x dx = ₀^ 2 x x x dx aligned & =2 ₀^ xdx =2[ x ]₀^ =2[ - 0] & =2(0)=0 aligned Option (A) is correct.

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