AP EAMCET202420 May 2024Morning ShiftMathematicsDefinite IntegrationActual
_ 1 [5] 31 ^ 1 [5] 242 1 [5] x³⁰+x²⁵ d x=
Options
- A65 4
- B-75 4
- C75 4
- D-65 4
Correct answer
D. -65 4
Step-by-step solution
I= _ 1 [5] 31 ^ 1 [5] 242 d x [5] x³⁰+x²⁵ I= _ 1 [5] 31 ^ 1 [5] 242 d x x^6 (1+x⁻⁵ )^ 1 / 5 1+x⁻⁵=t d t=-5 x⁻⁶ d xx= 1 [5] 31 t=32, x= 1 [5] 242 t=243I= ₃₂²⁴³ -t^ -1 / 5 d t 5 = -1 5 ( 5 4 ) [t^ 4 / 5 ]₃₂²⁴³=- 1 4 (81-16)= -65 4