NDA2024MathematicsDifferential EquationsActual
Paragraph: Let y d x+ (x-y^3 ) d y=0 be a differential equation. Question: What is the solution of the differential equation?
Options
- Ay^4+2 x=c
- By^4+3 x=c
- C2 x y^4+x=c
- D4 x y-y^4=c
Correct answer
D. 4 x y-y^4=c
Step-by-step solution
Given differential equation is y d x d y +x=y^3 d x d y +x 1 y =y^2 (Linear differential equation form d x d y +p x= ) If = e ^ 1 y dy = y x(I . F)= (I f) y^2 d y x y= y^3 d y 4 x y-y^4+c