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NDA 2025
Exam
NDA
Year
2025
Subject
Mathematics
Chapter
Hyperbola

NDA 2025 · Mathematics · Hyperbola

What is the distance between the two foci of the hyperbola 25x^2 -...

What is the distance between the two foci of the hyperbola 25x2−75y2=22525x^2 - 75y^2 = 225?

Options

  1. A232\sqrt{3} units
  2. B434\sqrt{3} units
  3. C6\sqrt{6} units
  4. D262\sqrt{6} units

Correct answer

B. 434\sqrt{3} units

Step-by-step solution

The given equation of the hyperbola is 25x2−75y2=22525x^2 - 75y^2 = 225.

Dividing the entire equation by 225225, we get:

x29−y23=1\dfrac{x^2}{9} - \dfrac{y^2}{3} = 1

Comparing this with the standard equation of a hyperbola x2a2−y2b2=1\dfrac{x^2}{a^2} - \dfrac{y^2}{b^2} = 1, we have a2=9a^2 = 9 and b2=3b^2 = 3.

The relation between aa, bb, and the distance from the center to a focus cc is given by c2=a2+b2c^2 = a^2 + b^2.

Substituting the values, we get:

c2=9+3=12c^2 = 9 + 3 = 12

c=12=23c = \sqrt{12} = 2\sqrt{3}

The distance between the two foci is 2c2c.

Distance =2(23)=43= 2(2\sqrt{3}) = 4\sqrt{3} units.

Answer: 434\sqrt{3} units
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