Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET20224 Jul 2022Morning ShiftMathematicsDefinite IntegrationActual

∫ 0 π x sin 2 sin x + cos 2 cos x d x =

Options

  1. Aπ 2
  2. Bπ 2 2
  3. C2 π
  4. Dπ 4

Correct answer

B. π 2 2

Step-by-step solution

I = ∫ 0 π x sin 2 sin x + cos 2 cos x d x = ∫ 0 π π - x sin 2 sin x + cos 2 cos x d x ⇒ 2 I = π ∫ 0 π sin 2 sin x + cos 2 cos x d x = 2 π ∫ 0 π 2 sin 2 sin x + cos 2 cos x d x ⇒ I = π ∫ 0 π 2 sin 2 sin x + cos 2 cos x d x     . . . i I = π ∫ 0 π 2 sin 2 sin π 2 - x + cos 2 cos π 2 - x d x I = π ∫ 0 π 2 sin 2 cos x + cos 2 sin x d x       . . . i i Adding both the

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

₀^1 2 x+5 x^2+3 x+2 ~d x= 2025₀^1 x^ 5 / 2 (1-x)^ 3 / 2 ~d x= 2025_ n [ 1 n^2 ^2 1 n^2 + 2 n^2 ^2 4 n^2 + 3 n^2 ^2 9 n^2 + + 1 n^2 ^2 1 ]= 2025₀^1 x Sin ⁻¹ x d x= 2025_ - 2 ^ 2 (x-[x]) d x= 2025₀^2 x^2(2-x)^5 d x= 2025If f(x)= Max x^3-4, x^4-4 , and g(x)= Min x^2, x^3 , then _ -1 ^1(f(x)-g(x)) d x= 2025_ n 2 n [ 2 n + 2 2 n + 3 2 n + + 2 ]= 2025 Full Definite Integration list All AP EAMCET PYQs