For the following two (02) items: There are 8 points on a plane out...

Total number of points is $8$.

Number of collinear points is $4$.

Total number of ways to select $4$ points from $8$ points is ^{8}C_{4} = 70$.<br><br>A quadrilateral cannot be formed if 3$ or $4$ selected points are collinear.

Number of ways to select $4$ collinear points is ^{4}C_{4} = 1$.<br><br>Number of ways to select 3$ collinear points and $1$ non-collinear point is ^{4}C_{3} \times ^{4}C_{1} = 4 \times 4 = 16$.<br><br>Total number of quadrilaterals that can be formed is 70 - (1 + 16) = 53$.

Answer: $53$