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NDA2024MathematicsPermutation and CombinationActual

If 26!= _n 8^k , where k and n are positive integers, then what is the maximum value of k ?

Options

  1. A6
  2. B7
  3. C8
  4. D9

Correct answer

B. 7

Step-by-step solution

26!=n 8^k=n 2^ 3 k Maximum power of 2 aligned & = [ 26 2 ]+ [ 26 4 ]+ [ 26 8 ]+ [ 26 16 ] & =13+6+3+1=23 aligned But power of 2=3 k Maximum value of 3 k=21 Hence, the maximum value of k=7 .

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