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NDA 2024
Exam
NDA
Year
2024
Subject
Mathematics
Chapter
Permutation and Combination

NDA 2024 · Mathematics · Permutation and Combination

If 26!= _n 8^k , where k and n are positive integers, then what is...

If 26!=n8k26!={ }_n 8^k, where kk and nn are positive integers, then what is the maximum value of kk ?

Options

  1. A6
  2. B7
  3. C8
  4. D9

Correct answer

B. 7

Step-by-step solution

∵26!=n8k=n23k\because 26!=n 8^k=n 2^{3 k} Maximum power of 2 =[262]+[264]+[268]+[2616]=13+6+3+1=23\begin{aligned} & =\left[\frac{26}{2}\right]+\left[\frac{26}{4}\right]+\left[\frac{26}{8}\right]+\left[\frac{26}{16}\right] \\ & =13+6+3+1=23 \end{aligned} But power of 2=3k∴2=3 k\therefore Maximum value of 3k=213 k=21 Hence, the maximum value of k=7k=7.
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