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NDA 2025
Exam
NDA
Year
2025
Subject
Mathematics
Chapter
Permutation and Combination

NDA 2025 · Mathematics · Permutation and Combination

For the following two (02) items: There are 8 points on a plane out...

For the following two (02) items:
There are 8 points on a plane out of which 4 points are collinear.

How many triangles can be formed by joining these points?

Options

  1. A5656
  2. B5454
  3. C5353
  4. D5252

Correct answer

D. 5252

Step-by-step solution

Total number of points on the plane is n=8n = 8.

Number of collinear points is m=4m = 4.

The total number of triangles that can be formed by joining nn points out of which mm are collinear is given by nC3−mC3^{n}C_{3} - ^{m}C_{3}.

Substituting the values, we get 8C3−4C3^{8}C_{3} - ^{4}C_{3}.

8C3=8×7×63×2×1=56^{8}C_{3} = \dfrac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56

4C3=4×3×23×2×1=4^{4}C_{3} = \dfrac{4 \times 3 \times 2}{3 \times 2 \times 1} = 4

Total number of triangles =56−4=52= 56 - 4 = 52.

Answer: 5252
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