Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NDA 2021
Exam
NDA
Year
2021
Subject
Mathematics
Chapter
Permutation and Combination

NDA 2021 · Mathematics · Permutation and Combination

Let S=\ 2,3,4,5,6,7,9\ . How many different 3-digit numbers (with...

Let S={2,3,4,5,6,7,9}S=\{2,3,4,5,6,7,9\}. How many different 3-digit numbers (with all digits different) from SS can be made which are less than 500 ?

Options

  1. A30
  2. B49
  3. C90
  4. D147

Correct answer

C. 90

Step-by-step solution

∴n(s)=7\therefore n(s)=7 For 3 digit numbers less than 500 (repetion not allowed) Numbers of digits choice for hundred place (2,3,4)=3(2,3,4)=3 Numbers of digits choice for tens place =6=6 Numbers of digits choice for once place =5∴=5\therefore Total number of 3 digit numbers less than 500 =3×6×5=90=3 \times 6 \times 5=90
Practice Permutation and Combination on Quantrex Academy →

More from Permutation and Combination

All Permutation and Combination questions Full Permutation and Combination list Permutation and Combination JEE Maths PYQsJEE Mathematics PYQs All NDA PYQs