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NDA2018MathematicsPermutation and CombinationActual

Where A^ is the complement of A . Let x be the number of integers lying between 2999 and 8001 which have at least two digits equal. Then x is equal to

Options

  1. A2480
  2. B2481
  3. C2482
  4. D2483

Correct answer

B. 2481

Step-by-step solution

Number of numbers between 2999 and 8001 =8001-2999-1=5001 array |l|l|l|l| 3 & & & array Number of numbers with all digit distinct and having 3 as starting digit =9 8 7=504 Number of numbers with all digit distinct and having 4 as starting digit. Similarly number of numbers with starting digit 5, 6 and 7 respectively are 504, 504 and 504. Total numbers =5 504=2520 Hence, required number =5001-2520=2481

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