Three dice having digits 1,2,3,4,5 and 6 on their faces are marked I, II and III and rolled. Let x, y and z represent the number on die = I die = II and die -III respectively. What is the number of possible outcomes such that x y z ?

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Correct answer: D. 20

Total number of ways =10+6+3+1=20

Three dice having digits 1,2,3,4,5 and 6 on their faces are marked I, II and III and rolled. Let x, y and z represent the number on die = I die = II and die -III respectively. What is the number of possible outcomes such that x y z ?

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