Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NDA 2018
Exam
NDA
Year
2018
Subject
Mathematics
Chapter
Permutation and Combination

NDA 2018 · Mathematics · Permutation and Combination

What is the number of triangles that can be formed by choosing the...

What is the number of triangles that can be formed by choosing the vertices from a set of 12 points in a plane, seven of which lie on the same straight line?

Options

  1. A185
  2. B175
  3. C115
  4. D105

Correct answer

A. 185

Step-by-step solution

To form a triangle, we need 3 points. 12 points are given. So, 12C3{ }^{12} \mathrm{C}_3 triangles can be formed. But, given that 7 points are on a straight line. selecting 3 points from this set will not form a triangle. So, number of triangles formed =12C3−7C3={ }^{12} \mathrm{C}_3-{ }^7 \mathrm{C}_3=12!3!9!−7!3!4!=12×11×103×2×1−7×6×53×2×1=220−35=185\begin{aligned} & =\frac{12!}{3!9!}-\frac{7!}{3!4!} \\ & =\frac{12 \times 11 \times 10}{3 \times 2 \times 1}-\frac{7 \times 6 \times 5}{3 \times 2 \times 1}=220-35=185 \end{aligned}$$
Practice Permutation and Combination on Quantrex Academy →

More from Permutation and Combination

All Permutation and Combination questions Full Permutation and Combination list Permutation and Combination JEE Maths PYQsJEE Mathematics PYQs All NDA PYQs