Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NDA 2018
Exam
NDA
Year
2018
Subject
Mathematics
Chapter
Permutation and Combination

NDA 2018 · Mathematics · Permutation and Combination

How many four-digit numbers divisible by 10 can be formed using...

How many four-digit numbers divisible by 10 can be formed using 1,5,0,6,71,5,0,6,7 without repetition of digits?

Options

  1. A2424
  2. B33
  3. C44
  4. D64

Correct answer

A. 2424

Step-by-step solution

A number divisible by 10 means the last digit is 0. So, the remaining 3 digits can be arranged in 4×3×24 \times 3 \times 2 ways =24=24 ways.
Practice Permutation and Combination on Quantrex Academy →

More from Permutation and Combination

All Permutation and Combination questions Full Permutation and Combination list Permutation and Combination JEE Maths PYQsJEE Mathematics PYQs All NDA PYQs