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NDA 2016
Exam
NDA
Year
2016
Subject
Mathematics
Chapter
Permutation and Combination

NDA 2016 · Mathematics · Permutation and Combination

What is the number of odd integers between 1000 and 9999 with no...

What is the number of odd integers between 1000 and 9999 with no digit repeated?

Options

  1. A21002100
  2. B21202120
  3. C22402240
  4. D33313331

Correct answer

C. 22402240

Step-by-step solution

Case I When unit digit can be 1,3,51,3,5 or 7&7 \& digit at thousand's place can be 1,2,3,4,5,6,71,2,3,4,5,6,7 or 8 . No. of ways digits can be filled are: \begin{array}{|l|l|l|l|}\hline7 & 8 & 7 & 4 \hline\end{array}Total no's =7×8×7×4=1568=7 \times 8 \times 7 \times 4=1568. Case II When unit digit can be 9&9 \& digit at thousand's place can be 1,2,3,4,5,6,71,2,3,4,5,6,7 or 8 . No. of ways digits can be filled are: \begin{array}{|l|l|l|l|}\hline8 & 8 & 7 & 1 \hline\end{array}Total no's =8×8×7×1=448=8 \times 8 \times 7 \times 1=448. Case III When unit digit can be 1,3,51,3,5 or 7&7 \& digit at thousand's place can be 9 . No. of ways digits can be filled are: \begin{array}{|l|l|l|l|}\hline1 & 8 & 7 & 4 \hline\end{array}Total no's =1×8×7×4=224=1 \times 8 \times 7 \times 4=224. ∴ Number of odd digits between 10009999 with no  digit repeated =1568+448+224=2240.\begin{aligned} \therefore \quad \text{ Number of odd digits between } 1000 & 9999 & \text{ with no } \\ \text{ digit repeated } & =1568+448+224 \\ & =2240 .\end{aligned}
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