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NDA 2012

Exam: NDA
Year: 2012
Subject: Mathematics
Chapter: Permutation and Combination

NDA 2012 · Mathematics · Permutation and Combination

What is the number of ways that 4 boys and 3 girls can be seated so...

What is the number of ways that 4 boys and 3 girls can be seated so that boys and girls alternate?

Options

A12
B72
C120
D144

Correct answer

D. 144

Step-by-step solution

B G B G B G B

4 \times 3 \times 3 \times 2 \times 2 \times 1 \times 1=144

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