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NDA2012MathematicsPermutation and CombinationActual

What is the number of ways that 4 boys and 3 girls can be seated so that boys and girls alternate?

Options

  1. A12
  2. B72
  3. C120
  4. D144

Correct answer

D. 144

Step-by-step solution

B G B G B G B 4 3 3 2 2 1 1=144

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