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NDA 2010
Exam
NDA
Year
2010
Subject
Mathematics
Chapter
Permutation and Combination

NDA 2010 · Mathematics · Permutation and Combination

What is the number of ways of arranging the letters of the word...

What is the number of ways of arranging the letters of the word 'BANANA' so that no two N's appear together?

Options

  1. A40
  2. B60
  3. C80
  4. D100

Correct answer

A. 40

Step-by-step solution

Total alphabets =6=6 Total no. of words =6!3!2!=7206×2=60=\frac{6!}{3!2!}=\frac{720}{6 \times 2}=60 Let two 'Ns' come together. Total no. of words =5!3!=\frac{5!}{3!} Reqd. numbers =60−20=40=60-20=40.
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