Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201923 Apr 2019Morning ShiftMathematicsDefinite IntegrationActual

( ₀^ 2 ^2 x x+ x d x= )

Options

  1. A( 3 2 ( 2 +1)^ 1 2 )
  2. B( 1 2 ( 2 +1) )
  3. C( 2 3 ( 3 +1) )
  4. D( 2 3 ( 2 -1) )

Correct answer

B. ( 1 2 ( 2 +1) )

Step-by-step solution

Let (I= ₀^ 2 ^2 x x+ x d x ) ...(i) On applying property ( ₀^a f(x) d x= ₀^a f(a-x) d x ), we get, (I= ₀^ 2 ^2 x x+ x d x ) ...(ii) On adding Eqs. (i) and (ii), we get ( aligned 2 I & = ₀^ 2 ^2 x+ ^2 x x+ x d x & = ₀^ 2 d x x+ x & = 1 2 ₀^ 2 cosec ( 4 +x ) d x & = 1 2 [ | cosec ( 4 +x )- ( 4 +x ) | ]₀^ / 2 I & = 1 2 2 [ ( 2 +1)- ( 2 -1)] & = 1 2 2 [2 ( 2 +1)]= 1 2 ( 2 +1) aligned ) Hence, option (b) is correct.

Practice Definite Integration on Quantrex Academy →

More from Definite Integration

₀^1 2 x+5 x^2+3 x+2 ~d x= 2025₀^1 x^ 5 / 2 (1-x)^ 3 / 2 ~d x= 2025_ n [ 1 n^2 ^2 1 n^2 + 2 n^2 ^2 4 n^2 + 3 n^2 ^2 9 n^2 + + 1 n^2 ^2 1 ]= 2025₀^1 x Sin ⁻¹ x d x= 2025_ - 2 ^ 2 (x-[x]) d x= 2025₀^2 x^2(2-x)^5 d x= 2025If f(x)= Max x^3-4, x^4-4 , and g(x)= Min x^2, x^3 , then _ -1 ^1(f(x)-g(x)) d x= 2025_ n 2 n [ 2 n + 2 2 n + 3 2 n + + 2 ]= 2025 Full Definite Integration list All AP EAMCET PYQs