NDA2024MathematicsQuadratic EquationActual
The roots of the equation 7 x^2-6 x+1=0 are and , where 2 and 2 are the angles of a triangle. Which one of the following is correct?
Options
- AThe triangle is equilateral
- BThe triangle is isosceles but not right-angled
- CThe triangle is right-angled
- DThe triangle is right-angled isosceles
Correct answer
C. The triangle is right-angled
Step-by-step solution
Since , are roots of 7 x^2-6 x+1=0 Sum of roots = + = 6 7 ...(i) Product of roots = = 1 7 ....(ii) ( + )= + 1- = ( 6 7 ) 1- 1 7 =1 + =45^ 2 +2 =90^ Which means 3^ rd angle of triangle is 90^ . Hence, triangle is right-angled triangle. Now consider, aligned & ( - )= ( + )^2-4 & = ( 6 7 )^2-4 ( 1 7 ) = 2 2 7 aligned Thus, ( - )= - 1+ = 1 2 2 and ( - )= 2 ( - ) 1- ^2( - ) = ( 4 2 7 ) 2 2 triangle is not an isosceles triangles.