Consider the following for the two (02) items that follow: The sum and the sum of squares of the observations corresponding to length X (in cm) and weight Y (in gm) of 50 tropical tubers are given as X = 200 , Y = 250 , X^2 = 900 and Y^2 = 1400 . Which one of the following is correct?

Step-by-step solution

Given n = 50 , X = 200 , Y = 250 , X^2 = 900 , and Y^2 = 1400 . The variance of X is calculated as: Var (X) = X^2 n - ( X n )^2 Var (X) = 900 50 - ( 200 50 )^2 Var (X) = 18 - (4)^2 = 18 - 16 = 2 The variance of Y is calculated as: Var (Y) = Y^2 n - ( Y n )^2 Var (Y) = 1400 50 - ( 250 50 )^2 Var (Y) = 28 - (5)^2 = 28 - 25 = 3 Comparing the variances, we get Var (X) Answer: Variance (X) < Variance (Y)