AP EAMCET2015MathematicsDefinite Integration
The slope of the tangent to the curve y= ₀^x 1 1+t^3 d t at the point, where x=1 is
Options
- A1 4
- B1 3
- C1 2
- D1
Correct answer
C. 1 2
Step-by-step solution
We have, y= ₀^x 1 1+t^3 d t Differentiating w.r.t. x , we get d y d x = 1 1+x^3 aligned & At x=1 & ( d y d x )_ x=1 = 1 1+1 = 1 2 aligned