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AP EAMCET2006MathematicsDefinite Integration

Dividing the interval [0,6] into 6 equal parts and by using trapezoidal rule the value of ₀^6 x^3 d x is approximately :

Options

  1. A330
  2. B331
  3. C332
  4. D333

Correct answer

D. 333

Step-by-step solution

By trapezoidal rule ₀^6 x^3 d x= h 2 y₀+y₆+2 (y₁+y₂ . . . .+y₃+y₄+y₅ ) = 1 2 0+216+2(1+8+27+64+125) = 1 2 216+450 = 666 2 =333

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