The approximate value of ₂ x^2 d x by using trapezoidal rule with 4 equal intervals, is

Step-by-step solution

Here, aligned n=4, h= 9-1 4 =2 y₀=f(1)=(1)^2=1 y₁=f(3)=(3)^2=9 y₂=f(5)=(5)^2=25 y₃=f(7)=(7)^2=49 y₄=f(9)=(9)^2=81 aligned by trapezoidal rule aligned ₁^9 x^2 d x & = h 2 [y₀+2 (y₁+y₂+y₃ )+y₄ ] & = 1 2 2[1+2(9+25+49)+81]=248 aligned