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NEET2026ChemistrySome Basic Concepts of ChemistryActual

When 1 dm ^3 of CO ₂ gas is passed over hot coke, the volume of gaseous mixture after complete reaction at STP becomes 1.4 dm ^3 . The composition of the gaseous mixture at STP is :

Options

  1. A0.8 dm ^3 of CO, 0.8 dm ^3 of CO ₂
  2. B0.8 dm ^3 of CO, 0.6 dm ^3 of CO ₂
  3. C0.6 dm ^3 of CO, 0.8 dm ^3 of CO ₂
  4. D0.6 dm ^3 of CO, 0.4 dm ^3 of CO ₂

Correct answer

B. 0.8 dm ^3 of CO, 0.6 dm ^3 of CO ₂

Step-by-step solution

The reaction of carbon dioxide with hot coke is given by: CO ₂(g) + C (s) 2 CO (g) Initial volume of CO ₂ = 1 dm ^3 Let x dm ^3 of CO ₂ react with hot coke. Volume of CO ₂ remaining = 1 - x dm ^3 Volume of CO formed = 2x dm ^3 Total volume of the gaseous mixture = (1 - x) + 2x = 1 + x dm ^3 Given that the total volume after the reaction is 1.4 dm ^3 : 1 + x = 1.4 x = 0.4 dm ^3 Volume of CO ₂ remaining = 1 - 0.4 = 0.6 dm ^3 Volume of CO formed = 2 0.4 = 0.8 dm ^3 The composition of the gaseous mixture is 0.8 dm ^3 o

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