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The right option for the mass of CO 2 produced by heating 20   g of 20 % pure limestone is (Atomic mass of Ca = 40 ) CaCO 3 → 1200   K CaO + CO 2

Options

  1. A1 . 32   g
  2. B1 . 12   g
  3. C1 . 76   g
  4. D2 . 64   g

Correct answer

C. 1 . 76   g

Step-by-step solution

CaCO 3 → 1200   K CaO + CO 2 According to the given equation, 100 grams of calcium carbonate gives 44 grams of carbon dioxide. Given that 20 grams of 20% pure lime stone, it means the given lime stone contain 4 grams of CaCO 3 . Hence, the maximum amount of CO 2 produced = 4 × 44 100 = 1 . 76   g

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