Which one of the followings has maximum number of atoms?

Number of atoms $= \dfrac{w}{molarmass} \times {N}_{A} \times atomicity$

Number of atoms in $1g of Li\left(s\right) = \dfrac{1}{7} \times$ {N}_{A} \times 1$</p><p>Number of atoms$1g of Ag\left(s\right)=\dfrac{1}{108}$\times {N}_{A} \times 1$

Number of atoms $1g of Mg\left(s\right)=\dfrac{1}{24}$ \times {N}_{A} \times 1$</p><p>Number of atoms$1g of {O}_{2}\left(g\right)=\dfrac{1}{32} \times {N}_{A} \times 2