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NEET2014ChemistrySome Basic Concepts of ChemistryActual

When 22.4 litres of H 2 g is mixed with 11.2 litres of C l 2 g , each at STP, the moles of H C l g formed is equal to

Options

  1. A1 m o l o f H C l g
  2. B2 m o l o f H C l g
  3. C0.5 mol H C l g
  4. D1.5 m o l o f H C l g

Correct answer

A. 1 m o l o f H C l g

Step-by-step solution

H 2 22.4 lt ⁡ + C l 2 11.2 lt ⁡ → 2 H C l 1 m o l e = 1 2 m o l e Limiting reagent is C l 2 . So, 1 mole H C l is formed.

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