What volume of oxygen gas (O_2) measured at 0^ C and 1 ~atm , is needed to burn completely 1 ~L of propane gas (C_3 H_8) measured under the same conditions?

Correct answer: C. 5 ~L Key Idea : Volume of a gas at S T P=22.4 ~L aligned & C_3 H_8+5 O_2 3 CO_2+4 H_2 O & 22.4 ~L 5 × 22.4 ~L aligned To burn 22.4 ~L C_3 H_8 the oxygen required is =5 × 22.4 ~L To burn 1 LC_3 H_8 the oxygen required will be aligned & =(5 × 22.4)/(22.4) & =5 ~L aligned

NEET 2008

Exam: NEET
Year: 2008
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

NEET 2008 · Chemistry · Some Basic Concepts of Chemistry

What volume of oxygen gas (O_2) measured at 0^ C and 1 ~atm , is...

What volume of oxygen gas

\left(\mathrm{O}_2\right)

measured at

0^{\circ} \mathrm{C}

and

1 \mathrm{~atm}

, is needed to burn completely

1 \mathrm{~L}

of propane gas

\left(\mathrm{C}_3 \mathrm{H}_8\right)

measured under the same conditions?

Options

A $7 \mathrm{~L}$
B $6 \mathrm{~L}$
C $5 \mathrm{~L}$
D $10 \mathrm{~L}$

Correct answer

C. $5 \mathrm{~L}$

Step-by-step solution

Key Idea : Volume of a gas at

S T P=22.4 \mathrm{~L}

\begin{aligned} & \mathrm{C}_3 \mathrm{H}_8+5 \mathrm{O}_2 \longrightarrow 3 \mathrm{CO}_2+4 \mathrm{H}_2 \mathrm{O} \\ & 22.4 \mathrm{~L} \quad 5 \times 22.4 \mathrm{~L} \end{aligned}

\because

To burn

22.4 \mathrm{~L} \mathrm{C}_3 \mathrm{H}_8

the oxygen required is

=5 \times 22.4 \mathrm{~L} \therefore

To burn

1 \mathrm{LC}_3 \mathrm{H}_8

the oxygen required will be

\begin{aligned} & =\frac{5 \times 22.4}{22.4} \\ & =5 \mathrm{~L} \end{aligned}

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