Concentrated of aqueous sulphuric acid is 98 \% H_2 SO_4 by mass and has a density of 1.80 ~g ~mL^ -1 Volume of acid required to make one litre of 0.1 M H_2 SO_4 solution is:

Correct answer: C. 5.55 ~mL Molarity of H_2 SO_4 solution =(98 × 1000)/(98 × 100) × 1.84=18.4 Suppose V ml of this H_2 SO_4 is used to prepare 1 . of 0.1 M H_2 SO_4 aligned & V × 18.02=1000 × 0.1 & ~V=(1000 × 0.1)/(18.02)=5.55 ml aligned

NEET 2007

Exam: NEET
Year: 2007
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

NEET 2007 · Chemistry · Some Basic Concepts of Chemistry

Concentrated of aqueous sulphuric acid is 98 \% H_2 SO_4 by mass...

Concentrated of aqueous sulphuric acid is

98 \% \mathrm{H}_2 \mathrm{SO}_4

by mass and has a density of

1.80 \mathrm{~g} \mathrm{~mL}^{-1}

Volume of acid required to make one litre of

0.1 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4

solution is:

Options

A $16.65 \mathrm{~mL}$
B $22.20 \mathrm{~mL}$
C $5.55 \mathrm{~mL}$
D $11.10 \mathrm{~mL}$

Correct answer

C. $5.55 \mathrm{~mL}$

Step-by-step solution

Molarity of

\mathrm{H}_2 \mathrm{SO}_4

solution

=\frac{98 \times 1000}{98 \times 100} \times 1.84=18.4

Suppose

\mathrm{V} \mathrm{ml}

of this

\mathrm{H}_2 \mathrm{SO}_4

is used to prepare 1 . of

0.1 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4

\begin{aligned} & \therefore \mathrm{V} \times 18.02=1000 \times 0.1 \\ & \mathrm{~V}=\frac{1000 \times 0.1}{18.02}=5.55 \mathrm{ml} \end{aligned}

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