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NEET 2003
Exam
NEET
Year
2003
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

NEET 2003 · Chemistry · Some Basic Concepts of Chemistry

In Haber process 3 litres of dihydrgen and 30 litres of dinitrogen...

In Haber process 3 litres of dihydrgen and 30 litres of dinitrogen were taken for reaction which yielded only 50%50 \% of the expected product. What will be the composition of gaseous mixture under the above said condition in the end?

Options

  1. A20 litres ammonia, 20 litres nitrogen, 20 litres hydrogen
  2. B10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen
  3. C20 litres ammonia, 10 litres nitrogen, 30 litres hydrogen
  4. D20 litres ammonia, 25 litres nitrogen, 15 litres hydrogen

Correct answer

B. 10 litres ammonia, 25 litres nitrogen, 15 litres hydrogen

Step-by-step solution

\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_31 \mathrm{ mol} \quad 3 \mathrm{ mol} 2 \mathrm{ mol}2vol2 vol3 \mathrm{ mol} 2 \mathrm{vol}(\operatorname{mol} \%=\operatorname{vol} \%) 10vol30vol20vol (expected = product) (30−x)(30−x)2x Given that  2x=20×50100=10∴x=5\begin{aligned}& \begin{array}{l}10 \mathrm{vol} \quad30 \mathrm{vol} \quad20 \mathrm{vol}\\ \text{ (expected = product) } \end{array}\\ & (30-x)(30-x) 2 x \\ \text{ Given\text{ that } }2 x=20 \times \frac{50}{100}=10 \\ & \therefore \quad x=5 \end{aligned}Compositionofofgaseous mixture N2=(30−x)=25 litre H2=(30−3x)=15 litre NH3=2x=10 litre \begin{aligned}\mathrm{N}_{2}& =(30-x)=25 \text{ litre }\\ \mathrm{H}_{2} & =(30-3 x)=15 \text{ litre }\\ \mathrm{NH}_{3}& =2 x=10 \text{ litre } \end{aligned}
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