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NEET2022PhysicsCenter of Mass, Momentum and CollisionActual

A shell of mass m is at rest initially. It explodes into three fragments having mass in the ratio 2 : 2 : 1 . If the fragments having equal mass fly off along mutually perpendicular directions with speed v , the speed of the third (lighter) fragment is:

Options

  1. A2 v
  2. B2 2 v
  3. C3 2 v
  4. Dv

Correct answer

B. 2 2 v

Step-by-step solution

The speed of the third particle will be along angle bisector of the other two velocities. Applying the conservation of momentum, m v ' = 2 m v cos 45 ° + 2 m v cos 45 ° ⇒ v ' = 2 2 v

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