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AP EAMCET202422 May 2024Evening ShiftMathematicsDifferentiationActual

If y=1+x+x^2+x^3+ .+ and |x| 1 , then y^ =

Options

  1. A2 y y^
  2. B2 y y^
  3. Cy^ 2 y
  4. D2 y^2 y^

Correct answer

A. 2 y y^

Step-by-step solution

aligned & y=1+x+x^2+x^3+ + y= 1 1-x y^ & = 1 (1-x)^2 y^ = 2 (1-x)^3 =2 y y^ aligned

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