NEET2026PhysicsLaws of MotionActual
The magnitude and direction of the acceleration produced in a body of mass 5 kg when two mutually perpendicular forces 8 N and 6 N act on it, are respectively :
Options
- A20 m s ⁻² ; ⁻¹(4/3) with 8 N force
- B2 m s ⁻² ; ⁻¹(3/4) with 6 N force
- C2 m s ⁻² ; ⁻¹(4/3) with 8 N force
- D2 m s ⁻² ; ⁻¹(3/4) with 8 N force
Correct answer
D. 2 m s ⁻² ; ⁻¹(3/4) with 8 N force
Step-by-step solution
Given forces are F₁ = 8 N and F₂ = 6 N acting perpendicular to each other. The magnitude of the net force is F = F₁^2 + F₂^2 = 8^2 + 6^2 = 10 N. The magnitude of acceleration is a = F m = 10 5 = 2 m s ⁻² . Let be the angle made by the net force with the 8 N force. = F₂ F₁ = 6 8 = 3 4 = ⁻¹ ( 3 4 ) with the 8 N force. Answer: 2 m s ⁻² ; ⁻¹(3/4) with 8 N force